Valid CNSP Exam Dumps Materials - CNSP Quiz Cram - PrepAwayETE
Valid CNSP Exam Dumps Materials - CNSP Quiz Cram - PrepAwayETE
Blog Article
Tags: CNSP Valid Test Experience, CNSP Premium Files, CNSP Reliable Test Camp, Latest Test CNSP Experience, CNSP Exam Outline
Our CNSP study guide is verified by professional expert, therefore they cover the most of knowledge points. By using the exam dumps of us, you can get a full training for the exam. CNSP exam dumps also have free update for 365 days after payment, and the update version will send to your email automatically. Furthermore, we have the online and offline chat service stuff, they can give you reply of your questions about the CNSP Exam Dumps. Also, you can send your problem by email, we will give you answer as quickly as we can.
Having a good command of processional knowledge in this line, they devised our high quality and high effective CNSP study materials by unremitting effort and studious research. They are meritorious and unsuspecting experts with professional background. By concluding quintessential points into CNSP Preparation engine, you can pass the exam with the least time while huge progress. And our pass rate of the CNSP exam questions is high as 98% to 100%.
>> CNSP Valid Test Experience <<
CNSP Premium Files - CNSP Reliable Test Camp
Many people now want to obtain the CNSP certificate. Because getting a certification can really help you prove your strength, especially in today's competitive pressure. The science and technology are very developed now. If you don't improve your soft power, you are really likely to be replaced. Our CNSP Exam Preparation can help you improve your uniqueness. And our CNSP study materials contain the most latest information not only on the content but also on the displays.
The SecOps Group Certified Network Security Practitioner Sample Questions (Q37-Q42):
NEW QUESTION # 37
Which SMB (Server Message Block) network protocol versions are vulnerable to the EternalBlue (MS17-010) Windows exploit?
- A. Both SMBv1 and SMBv2
- B. SMBv2 only
- C. SMBv1 only
- D. SMBv3 only
Answer: C
Explanation:
EternalBlue (MS17-010) is an exploit targeting a buffer overflow in Microsoft's SMB (Server Message Block) implementation, leaked by the Shadow Brokers in 2017. SMB enables file/printer sharing:
SMBv1 (1980s): Legacy, used in Windows NT/XP.
SMBv2 (2006, Vista): Enhanced performance/security.
SMBv3 (2012, Windows 8): Adds encryption, multichannel.
Vulnerability:
EternalBlue exploits a flaw in SMBv1's SRVNET driver (srv.sys), allowing remote code execution via crafted packets. Microsoft patched it in March 2017 (MS17-010).
Affected OS: Windows XP to Server 2016 (pre-patch), if SMBv1 enabled.
Proof: WannaCry/NotPetya used it, targeting port 445/TCP.
SMBv1 Only: The bug resides in SMBv1's packet handling (e.g., TRANS2 requests). SMBv2/v3 rewrote this code, immune to the specific overflow.
Microsoft: Post-patch, SMBv1 is disabled by default (Windows 10 1709+).
Security Implications: CNSP likely stresses disabling SMBv1 (e.g., via Group Policy) and patching, as EternalBlue remains a threat in legacy environments.
Why other options are incorrect:
B, C: SMBv2/v3 aren't vulnerable; the flaw is SMBv1-specific.
D: SMBv2 isn't affected, only SMBv1.
Real-World Context: WannaCry's 2017 rampage hit unpatched SMBv1 systems (e.g., NHS), costing billions.
NEW QUESTION # 38
Which of the following algorithms could be used to negotiate a shared encryption key?
- A. SHA1
- B. AES
- C. Triple-DES
- D. Diffie-Hellman
Answer: D
Explanation:
Negotiating a shared encryption key involves a process where two parties agree on a secret key over an insecure channel without directly transmitting it. This is distinct from encryption or hashing algorithms, which serve different purposes.
Why C is correct: The Diffie-Hellman (DH) algorithm is a key exchange protocol that enables two parties to establish a shared secret key using mathematical operations (e.g., modular exponentiation). It's widely used in protocols like TLS and IPsec, as noted in CNSP for secure key negotiation.
Why other options are incorrect:
A: Triple-DES is a symmetric encryption algorithm for data encryption, not key negotiation.
B: SHA1 is a hash function for integrity, not key exchange.
D: AES is a symmetric encryption algorithm, not a key exchange mechanism.
NEW QUESTION # 39
According to the screenshot below, which of the following statements are correct?
- A. The application is running on port 443 and the HTTPS protocol.
- B. The credentials have been submitted over the HTTPS protocol.
- C. The application is running on port 80 and the HTTP protocol.
- D. The credentials have been submitted over the HTTP protocol.
Answer: A
Explanation:
The screenshot is from Wireshark, a network protocol analyzer, displaying captured network traffic. The relevant columns include the source and destination IP addresses, ports, protocol, and additional information about the packets. Let's break down the details:
Destination Port Analysis: The screenshot shows multiple packets with a destination port of 443 (e.g., in the "Destination" column, entries like "172.72.61.9:443"). Port 443 is the default port for HTTPS (HTTP Secure), which is HTTP traffic encrypted using SSL/TLS. This indicates that the application is communicating over HTTPS.
Protocol Analysis: The "Protocol" column lists "TLSv1.2" for most packets (e.g., frame numbers 2000084, 2000086). TLS (Transport Layer Security) is the cryptographic protocol used by HTTPS to secure HTTP communications. This confirms that the traffic is HTTPS, not plain HTTP.
Packet Details: The "Info" column provides additional context, such as "Application Data" for TLS packets, indicating encrypted application-layer data (typical of HTTPS). There are also HTTP packets (e.g., frame 2000088), but these are likely part of the HTTPS session (e.g., HTTP/2 over TLS, as noted by "HTTP2").
Now, let's evaluate the options:
Option A: "The application is running on port 443 and the HTTPS protocol." This is correct. The destination port 443 and the use of TLSv1.2 confirm that the application is using HTTPS. HTTPS is the standard protocol for secure web communication, and port 443 is its designated port. CNSP documentation emphasizes that HTTPS traffic on port 443 indicates a secure application-layer protocol, often used for web applications handling sensitive data.
Option B: "The credentials have been submitted over the HTTP protocol." This is incorrect. HTTP typically uses port 80, but the screenshot shows traffic on port 443 with TLS, indicating HTTPS. Credentials submitted over this connection would be encrypted via HTTPS, not sent in plaintext over HTTP. CNSP highlights the security risks of HTTP for credential submission due to lack of encryption, which isn't the case here.
Option C: "The credentials have been submitted over the HTTPS protocol." While this statement could be true (since HTTPS is in use, any credentials would likely be submitted securely), the question asks for the "correct" statement based on the screenshot. The screenshot doesn't explicitly show credential submission (e.g., a POST request with form data); it only shows the protocol and port. Option A is more directly supported by the screenshot as it focuses on the application's protocol and port, not the specific action of credential submission. CNSP notes that HTTPS ensures confidentiality, but this option requires more specific evidence of credentials.
Option D: "The application is running on port 80 and the HTTP protocol." This is incorrect. Port 80 is the default for HTTP, but the screenshot clearly shows port 443 and TLS, indicating HTTPS. CNSP documentation contrasts HTTP (port 80, unencrypted) with HTTPS (port 443, encrypted), making this option invalid.
Conclusion: Option A is the most accurate and comprehensive statement directly supported by the screenshot, confirming the application's use of port 443 and HTTPS. While Option C might be true in a broader context, it's less definitive without explicit evidence of credential submission in the captured packets.
NEW QUESTION # 40
You are performing a security audit on a company's network infrastructure and have discovered the SNMP community string set to the default value of "public" on several devices. What security risks could this pose, and how might you exploit it?
- A. The potential risk is that an attacker could use the SNMP protocol to modify the devices' configuration settings. You might use a tool like Snmpset to change the settings.
- B. Both A and B.
- C. None of the above.
- D. The potential risk is that an attacker could use the SNMP protocol to gather sensitive information about the devices. You might use a tool like Snmpwalk to query the devices for information.
Answer: D
Explanation:
SNMP (Simple Network Management Protocol) uses community strings as a basic form of authentication. The default read-only community string "public" is widely known, and if left unchanged, it exposes devices to unauthorized access. The primary risk with "public" is information disclosure, as it typically grants read-only access, allowing attackers to gather sensitive data (e.g., device configurations, network topology) without altering settings.
Why A is correct: With the "public" string, an attacker can use tools like snmpwalk to enumerate device details (e.g., system uptime, interfaces, or software versions) via SNMP queries. This aligns with CNSP's focus on reconnaissance risks during security audits, emphasizing the danger of default credentials enabling passive data collection.
Why other options are incorrect:
B: While modifying settings is a risk with SNMP, the default "public" string is typically read-only. Changing configurations requires a read-write community string (e.g., "private"), which isn't implied here. Thus, snmpset would not work with "public" alone.
C: Since B is incorrect in this context, C (both A and B) cannot be the answer.
D: The risk in A is valid, so "none of the above" is incorrect.
NEW QUESTION # 41
What will be the subnet mask for 192.168.0.1/18?
- A. 255.255.255.0
- B. 255.255.192.0
- C. 255.225.192.0
- D. 255.225.225.0
Answer: B
Explanation:
An IP address with a /18 prefix (CIDR notation) indicates 18 network bits in the subnet mask, leaving 14 host bits (32 total bits - 18). For IPv4 (e.g., 192.168.0.1):
Binary Mask: First 18 bits are 1s, rest 0s.
1st octet: 11111111 (255)
2nd octet: 11111111 (255)
3rd octet: 11000000 (192)
4th octet: 00000000 (0)
Decimal: 255.255.192.0
Calculation:
Bits: /18 = 2